264. Byte Frequency Count

I'm a slow walker, but I never walk backwards.

Task Description

Write a program to read data from a file. Your program will open a file with binary read mode. (The file name is given in standard input.) The first four bytes of the file is a positive integer $n$, which is the number of data afterward. Then there are $n$ two byte signed integers ranging from -32768 to 32767 in binary format. Now you need to determine which number from -32768 to 32767 appears most. If there is a tie, report the largest one. For example, if both 1 and 10 appear 100 times, which is the maximum number of times, then you should report 10.

寫程式以二進制讀入一份檔案,檔案的前 4 個位元組為一個 32-bit 整數 $n$,表示接下來需要統計 16-bit 有號整數分別出現多少次。請輸出出現最多次的那個數,如果出現次數相同時,以最大的那一個為準。


There is a string with maximum length 200, specifying the file name. This string can be read by scanf("%s",...).

請根據標準輸入串流中 (也就是鍵盤輸入) 的第一行字串,作為開檔的檔案名稱,你可以假設不會有特殊的空白表達式,只接使用 scanf("%s",...) 即可。


You should output two lines. First line is the number that appears most, and the second line is the frequency of this number.


Sample Input


Sample Output



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