275. Set

Task Description

Build a library to process set of numbers from 0 to 63 Since a long long int has 64 bits, we can use a bit to present a number in the set. If the bit is 1 then the corresponding number is in the set, otherwise it is not in the set. You need to implement the following functions for set.

• void init(Set *set)
  This function set the set to be empty.
• void add(Set *set, int i)
  This function adds i into the set.
• void has(Set set, int i)
  This function prints a message to indicate if $i$ is in a set. For example, if $a$ is $\lbrace 3, 5, 2\rbrace $ and $i$ is $3$, then it will print set has 3. If $a$ is $\lbrace 3, 5, 2\rbrace $ and $i$ is $13$, then it will print set does not have 13.
• Set setUnion(Set a, Set b)
  This function returns the union of sets $a$ and $b$. For example, if $a$ is $\lbrace 3, 5, 2\rbrace $ and $b$ is $\lbrace 3, 7, 9\rbrace $, then the union of $a$ and $b$ is $\lbrace 3, 5, 2, 7, 9\rbrace $.
• Set setIntersect(Set a, Set b)
  This function returns the intersection of sets $a$ and $b$. For example, if $a$ is $\lbrace 3, 5, 2\rbrace $ and $b$ is $\lbrace 3, 7, 9\rbrace $, then the intersection of $a$ and $b$ is $\lbrace 3\rbrace $.
• Set setDifference(Set a, Set b)
  This function returns the difference between sets $a$ and $b$. For example, if $a$ is $\lbrace 3, 5, 2\rbrace $ and $b$ is $\lbrace 3, 7, 9\rbrace $, then the difference of $a$ and $b$ is $\lbrace 5, 2, 7, 9\rbrace $.

main.c

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#include <stdio.h>
#include "set.h"
 
int main()
{
  Set a, b, c;
 
  init(&a);
  add(&a, 3);
  add(&a, 5);
  add(&a, 2);
 
  init(&b);
  add(&b, 3);
  add(&b, 7);
  add(&b, 9);
 
  c = setUnion(a, b);
  has(c, 2);
  has(c, 3);
  has(c, 5);
  has(c, 7);
  has(c, 9);
 
  c = setIntersect(a, b);
  has(c, 2);
  has(c, 3);
  has(c, 5);
  has(c, 7);
  has(c, 9);
 
  c = setDifference(a, b);
  has(c, 2);
  has(c, 3);
  has(c, 5);
  has(c, 7);
  has(c, 9);
 
  return 0;
}

set.h

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typedef unsigned long long Set;
void init(Set *set);
void add(Set *set, int i);
void has(Set set, int i);
Set setUnion(Set a, Set b);
Set setIntersect(Set a, Set b);
Set setDifference(Set a, Set b);

Sample Output

set has 2
set has 3
set has 5
set has 7
set has 9
set does not have 2
set has 3
set does not have 5
set does not have 7
set does not have 9
set has 2
set does not have 3
set has 5
set has 7
set has 9